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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Hard
  • MCQ

The four arms of a Wheatstone bridge have resistances as shown in the figure. A  galvanometer of \(15\, \Omega\) resistance is connected across \(BD\). Calculate the current through the galvanometer when a potential difference of \(10\, V\) is maintained across \(AC.\)

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Answer & Solution

Correct Answer

(C) \(4.87\, mA\)

Step-by-step Solution

Detailed explanation

\(\frac{x-10}{100}+\frac{x-y}{15}+\frac{x-0}{10}=0\)

\(53 x-20 y=30 \ldots \ldots(1)\)

\(\frac{y-10}{60}+\frac{y-x}{15}+\frac{y-0}{5}=0\)

\(17 y -4 x =10\)

on solving \((1)\,\&\,(2)\)

\(x=0.865\)

\(y =0.792\)

\(\Delta V =0.073 R =15\, \Omega\)

\(i =4.87 \,mA\)

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