A \(NCC\) parade is going at a uniform speed of \(9\,km / h\) under a mango tree on which a monkey is sitting at a height of \(19.6\,m\). At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is \(...m\) (Given \(g=9.8\,m / s ^{2}\) )

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Answer & Solution

Correct Answer

(A) \(5\)

Step-by-step Solution

Detailed explanation

Time taken by mango \(=\sqrt{\frac{2 n}{g}}\)

\(=\sqrt{\frac{2 \times 19.6}{9.8}}=2 \text { second }\)

Distance \(= vt\)

\(=9 \times \frac{5}{18} \times 2=5\,m\)

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