JEE Mains · Physics · STD 11 - 3.2 motion in plane
A \(NCC\) parade is going at a uniform speed of \(9\,km / h\) under a mango tree on which a monkey is sitting at a height of \(19.6\,m\). At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is \(...m\) (Given \(g=9.8\,m / s ^{2}\) )
- A \(5\)
- B \(10\)
- C \(19.8\)
- D \(24.5\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
Time taken by mango \(=\sqrt{\frac{2 n}{g}}\) \(=\sqrt{\frac{2 \times 19.6}{9.8}}=2 \text { second }\) Distance \(= vt\) \(=9 \times \frac{5}{18} \times 2=5\,m\)
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