JEE Mains · Maths · STD 11 - 12. limits
\(\mathop {\lim }\limits_{x \to {1^ - }} \frac{{\sqrt \pi - \sqrt {2\,{{\sin }^{ - 1}}x} }}{{\sqrt {1 - x} }}\) is equal to
- A \(\frac{1}{{\sqrt {2\pi } }}\)
- B \(\sqrt {\frac{2}{\pi }} \)
- C \(\sqrt {\frac{\pi }{2}} \)
- D \(\sqrt \pi \)
Answer & Solution
Correct Answer
(B) \(\sqrt {\frac{2}{\pi }} \)
Step-by-step Solution
Detailed explanation
\(\mathop {\lim }\limits_{x \to {1^ - }} \frac{{\sqrt \pi - \sqrt {2{{\sin }^{ - 1}}x} }}{{\sqrt {1 - x} }} \times \frac{{\sqrt \pi + \sqrt {2{{\sin }^{ - 1}}x} }}{{\sqrt \pi + \sqrt {2{{\sin }^{ - 1}}x} }}\)…
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