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JEE Mains · Maths · STD 12 - 13. probability

The sum and product of the mean and variance of a binomial distribution are \(82.5\) and \(1350\) respectively. They the number of trials in the binomial distribution is.

  1. A \(92\)
  2. B \(93\)
  3. C \(94\)
  4. D \(96\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(96\)

Step-by-step Solution

Detailed explanation

Let, mean \(=m=n p\) \(and\) variance \(= v = npq , p + q =1\) Sum \(=m+v=\frac{165}{2}\) Product \(= mv =1350\) On solving, \(m = np =60\) \(v = npq =\frac{45}{2} \therefore q =\frac{3}{8} \therefore P =\frac{5}{8}\) Hence \(n =96\)
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