JEE Mains · Maths · STD 12 - 13. probability
The sum and product of the mean and variance of a binomial distribution are \(82.5\) and \(1350\) respectively. They the number of trials in the binomial distribution is.
- A \(92\)
- B \(93\)
- C \(94\)
- D \(96\)
Answer & Solution
Correct Answer
(D) \(96\)
Step-by-step Solution
Detailed explanation
Let, mean \(=m=n p\) \(and\) variance \(= v = npq , p + q =1\) Sum \(=m+v=\frac{165}{2}\) Product \(= mv =1350\) On solving, \(m = np =60\) \(v = npq =\frac{45}{2} \therefore q =\frac{3}{8} \therefore P =\frac{5}{8}\) Hence \(n =96\)
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