JEE Mains · Maths · STD 11 - Trigonometrical equations
Two poles standing on a horizontal ground are of heights \(5\,m\) and \(10\, m\) respectively. The line joining their tops makes an angle of \(15^o\) with ground. Then the distance (in \(m\)) between the poles, is
- A \(\frac{5}{2}\,\left( {2 + \sqrt 3 } \right)\)
- B \(5\,\left( {\sqrt 3 + 1} \right)\)
- C \(5\,\left( {2 + \sqrt 3 } \right)\)
- D \(10\,\left( {\sqrt 3 - 1} \right)\)
Answer & Solution
Correct Answer
(C) \(5\,\left( {2 + \sqrt 3 } \right)\)
Step-by-step Solution
Detailed explanation
\(\Delta ABC\, \Rightarrow \,\tan \,{15^o}\, = \,\frac{5}{x}\) \( \Rightarrow \,2\, - \,\sqrt 3 \, = \,\frac{5}{x}\) \( \Rightarrow \,x\, = \,5\,(2 + \sqrt 3 )\)
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