JEE Mains · Maths · STD 11 - 6. permutation and combination
Total number of \(6-\)digit numbers in which only and all the five digits \(1,3,5,7\) and \(9\) appear, is
- A \(\frac{5}{2}(6 !)\)
- B \(5^6\)
- C \(\frac{1}{2}(6 !)\)
- D \(6!\)
Answer & Solution
Correct Answer
(A) \(\frac{5}{2}(6 !)\)
Step-by-step Solution
Detailed explanation
Total number of 6 -digit numbers in which only and all the five digits \(1,3,5,7\) and \(9\) is \(^{5} \mathrm{C}_{1} \times \frac{6 !}{2 !}\)
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