JEE Mains · Maths · STD 11 - 8. sequence and series
The value of \(\sum\limits_{r = 16}^{30} {(r + 2)(r - 3)}\) is equal to
- A \(7770\)
- B \(7785\)
- C \(7775\)
- D \(7780\)
Answer & Solution
Correct Answer
(D) \(7780\)
Step-by-step Solution
Detailed explanation
\(\sum\limits_{r = 16}^{20} {({r^2} - r - 6 = 7780)}\)
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