JEE Mains · Maths · STD 11 - 13. statistics
Let sets \(A\) and \(B\) have \(5\) elements each. Let the mean of the elements in sets \(A\) and \(B\) be \(5\) and \(8\) respectively and the variance of the elements in sets \(A\) and \(B\) be \(12\) and \(20\) respectively \(A\) new set \(C\) of \(10\) elements is formed by subtracting \(3\) from each element of \(A\) and adding 2 to each element of B. Then the sum of the mean and variance of the elements of \(C\) is \(.......\).
- A \(32\)
- B \(38\)
- C \(40\)
- D \(36\)
Answer & Solution
Correct Answer
(B) \(38\)
Step-by-step Solution
Detailed explanation
\(\omega A=\left\{a_1, a_2, a_3, a_4, a_5\right\}\) \(B=\left\{b_1, b_2, b_3, b_4, b_5\right\}\) \(\text { Given, } \sum_{ i =1}^3 ai =25, \sum_{ i =1}^3 bi =40\)…
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