JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of four -digit numbers strictly greater than \(4321\) that can be formed using the digits \(0, 1, 2, 3, 4, 5\) (repetition of digits is allowed) is
- A \(360\)
- B \(288\)
- C \(310\)
- D \(306\)
Answer & Solution
Correct Answer
(C) \(310\)
Step-by-step Solution
Detailed explanation
Starting with \(5=6^3=216\) Starting with \(44=6^2=36\) Starting with \(45=6^2=36\) Starting with \(43=18\) (Not using \(0,1,2\) ) Starting with \(432=4\) Total \(=310\)
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