JEE Mains · Maths · STD 12 - 6. Application of derivatives
The tangent at the point \((2, -2)\) to the curve, \(x^2y^2 - 2x = 4\, (1 -y)\) does not pass through the point
- A \(\left( {4,\frac{1}{3}} \right)\)
- B \((8, 5)\)
- C \((-4, -9)\)
- D \((- 2, - 7)\)
Answer & Solution
Correct Answer
(D) \((- 2, - 7)\)
Step-by-step Solution
Detailed explanation
\({x^2}{y^2} - 2x = 4 - 4y\) Differentiate w.r.t.\('x'\) \(2x{y^2} + 2y.{x^2}.\frac{{dy}}{{dx}} - 2 = - 4.\frac{{dy}}{{dx}}\) \(\frac{{dy}}{{dx}}\left( {2y.{x^2} + 4} \right) = 2 - 2x.{y^2}\)…
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