JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The sum of diameters of the circles that touch \((i)\) the parabola \(75 x^{2}=64(5 y-3)\) at the point \(\left(\frac{8}{5}, \frac{6}{5}\right)\) and \((ii)\) the \(y\)-axis, is equal to \(......\)
- A \(0\)
- B \(1\)
- C \(100\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
\(x^{2}=\frac{64.5}{75}\left(y-\frac{3}{5}\right)\) equation of tangent at \(\left(\frac{8}{5}, \frac{6}{5}\right)\) \(x \cdot \frac{8}{5}=\frac{64}{15}\left(\frac{y+\frac{6}{5}}{2}-\frac{3}{5}\right)\) \(3 x-4 y=0\) equation of family of circle is…
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