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JEE Mains · Maths · STD 11 - 7. binomial theoram
The remainder when \((2023)^{2023}\) is divided by \(35\) is \(..........\).
- A \(7\)
- B \(14\)
- C \(21\)
- D \(28\)
Answer & Solution
Correct Answer
(A) \(7\)
Step-by-step Solution
Detailed explanation
\((2023)^{2023}\) \(=(2030-7)^{2023}\) \(=(35 K -7)^{2023}\) \(={ }^{2023} C _0(35 K )^{2023}(-7)^0+{ }^{2023} C _1(35 K )^{2022}(-7)+\ldots .+\) \(\ldots \ldots+{ }^{2023} C _{2023}(-7)^{2023}\) \(=35 N -7^{2023}\)…
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