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JEE Mains · Maths · STD 12 - 6. Application of derivatives

Let \(x, y\) be positive real numbers and \(m, n\) positive integers. The maximum value of the expression \(\frac{{{x^m}{y^n}}}{{\left( {1 + {x^{2m}}} \right)\,\left( {1 + {y^{2n}}} \right)}}\) is

  1. A \(1\)
  2. B \(\frac{1}{2}\)
  3. C \(\frac{1}{4}\)
  4. D \(\frac{{m + n}}{{6mn}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{4}\)

Step-by-step Solution

Detailed explanation

\(\frac{{{x^m}{y^n}}}{{\left( {1 + {x^{2m}}} \right)\left( {1 + {y^{2n}}} \right)}}\) \( = \frac{1}{{\left( {{x^m} + \frac{1}{{{x^m}}}} \right)\left( {{y^n} + \frac{1}{{{y^n}}}} \right)}}{\rm{ }}\) \({\rm{Put\,\, }}{x^m} + \frac{1}{{{x^m}}} \ge 2\)…
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