JEE Mains · Maths · STD 12 - 1. relation and function
The number of one-one function \(f :\{ a , b , c , d \} \rightarrow\) \(\{0,1,2, \ldots ., 10\}\) such that \(2 f(a)-f(b)+3 f(c)+\) \(f ( d )=0\) is
- A \(32\)
- B \(31\)
- C \(22\)
- D \(89\)
Answer & Solution
Correct Answer
(B) \(31\)
Step-by-step Solution
Detailed explanation
\(2 f(a)+3 f(c)=f(d)-f(b)\) Using fundamental principle of counting Number of one-one function is \(31\)
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