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JEE Mains · Maths · STD 12 - 13. probability

If the numbers appeared on the two throws of a fair six faced die are \(\alpha\) and \(\beta\), then the probability that \(x ^{2}+\alpha x+\beta>0\), for all \(x \in R\), is.

  1. A \(\frac{17}{36}\)
  2. B \(\frac{4}{9}\)
  3. C \(\frac{1}{2}\)
  4. D \(\frac{19}{36}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{17}{36}\)

Step-by-step Solution

Detailed explanation

\(x^{2}+\alpha x+\beta>0, \forall x \in R\) \(D=\alpha^{2}-4 \beta<0\) \(\alpha^{2}<4 \beta\) Total cases \(=6 \times 6=36\) Fav. cases \(=\beta=1, \alpha=1\) \(\beta=2, \alpha=1,2\) \(\beta=3, \alpha=1,2,3\) \(\beta=4, \alpha=1,2,3\) \(\beta=5, \alpha=1,2,3,4\)…