JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of five digit numbers, greater than \(40000\) and divisible by \(5\), which can be formed using the digits \(0,1,3,5,7\) and \(9\) without repetition, is equal to
- A \(120\)
- B \(132\)
- C \(72\)
- D \(96\)
Answer & Solution
Correct Answer
(A) \(120\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{lllll}5 & x & x & x & 0 \\ 7 & x & x & x & 0 \\ 7 & x & x & x & 5 \\ 9 & x & x & x & 0 \\ 9 & x & x & x & 5\end{array}\) So Required numbers \(=5 \times{ }^4 P _3=120\)
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