JEE Mains · Maths · STD 12 - 11. three dimension geometry
The distance of the point \((7,-3,-4)\) from the plane passing through the points \((2,-3,1),(-1,1,-2)\) and \((3,-4,2)\) is:
- A \(4\)
- B \(5\)
- C \(5 \sqrt{2}\)
- D \(4 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(5 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Equation of Plane is \(=\left|\begin{array}{ccc}x-2 & y+3 & z-1 \\-3 & 4 & -3 \\4 & -5 & 4\end{array}\right|=0\) \(x - z -1=0\) Distance of \(P(7,-3,-4)\) from Plane is \(d =\left|\frac{7+4-1}{\sqrt{2}}\right|=5 \sqrt{2}\)
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