JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
The equation of circle described on the chord \(3x + y+ 5\, = 0\) of the circle \(x^2 + y^2\, = 16\) as diameter is
- A \(x^2 +y^2 +3x +y-11\, = 0\)
- B \(x^2 +y^2 +3x +y+1\, = 0\)
- C \(x^2 +y^2 +3x +y-2 \,= 0\)
- D \(x^2 +y^2 +3x +y-22\, = 0\)
Answer & Solution
Correct Answer
(A) \(x^2 +y^2 +3x +y-11\, = 0\)
Step-by-step Solution
Detailed explanation
Given circle is \({x^2} + {y^2} - 16 = 0\) Eqn. of chord say \(AB\) of given circle is \(3x + y + 5 = 0\) Equation of required circle is \({x^2} + {y^2} - 16 + \lambda \left( {3x + y + 5} \right) = 0\)…
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