JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The equation of a common tangent to the parabolas \(y = x ^{2}\) and \(y =-( x -2)^{2}\) is.
- A \(y=4(x-2)\)
- B \(y=4(x-1)\)
- C \(y=4(x+1)\)
- D \(y=4(x+2)\)
Answer & Solution
Correct Answer
(B) \(y=4(x-1)\)
Step-by-step Solution
Detailed explanation
Equation of tangent of \(y = x ^{2}\) be \(t x=y+a t^{2}\) \(y=t x-\frac{t^{2}}{4}\) Solve with \(y=-(x-2)^{2}\) \(tx -\frac{ t ^{2}}{4}=-( x -2)^{2}\) \(x^{2}+x(t-4)-\frac{t^{2}}{4}+4=0\) \(D =0\) \(( t -4)^{2}-4 \cdot\left(4-\frac{ t ^{2}}{4}\right)=0\) \(t ^{2}-4 t =0\)…
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