JEE Mains · Maths · STD 11 - 6. permutation and combination
Let \(A\) and \(B\) be two sets containing four and two elements respectively. Then the number of subsets of the set \(A \times B,\) each having at least three elements is :
- A \(510\)
- B \(219\)
- C \(256\)
- D \(275\)
Answer & Solution
Correct Answer
(B) \(219\)
Step-by-step Solution
Detailed explanation
\(A=\{x, y\}\) \(B=\{a, b, c, d\}\) \(a \times B\) having \(2 \times 4=8\) elements Total substance of \(A \times B\) is \(2^{8}=256\) \(\therefore\) Total no. of subsets of \(A \times B\) having \(3\) or more elements \(=256 - 1 \) null set \(+8\) single ton set…
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