JEE Mains · Maths · STD 12 - 7.1 indefinite integral
\(\smallint \frac{{{{\sin }^2}x{{\cos }^2}x}}{{{{\left( {{{\sin }^5}x + {{\cos }^3}x{{\sin }^2}x + {{\sin }^3}x{{\cos }^2}x + {{\cos }^5}x} \right)}^2}}}dx\)
- A \(\frac{{ - 1}}{{3\left( {1 + {{\tan }^3}x} \right)}} + c\)
- B \(\frac{1}{{1 + {{\cot }^3}x}} + c\)
- C \(\frac{{ - 1}}{{1 + {{\cot }^3}x}} + c\)
- D \(\frac{{ - 1}}{{3\left( {1 + {{\tan }^3}x} \right)}} + c\)
Answer & Solution
Correct Answer
(A) \(\frac{{ - 1}}{{3\left( {1 + {{\tan }^3}x} \right)}} + c\)
Step-by-step Solution
Detailed explanation
\({=\int \frac{\sin ^{2} x \cos ^{2} x}{\left(\sin ^{5} x+\cos ^{3} x \sin ^{2} x+\sin ^{3} x \cos ^{2} x+\cos ^{5} x\right)^{2}} d x} \)…
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