JEE Mains · Maths · STD 11 - 4.1 complex nubers
For \(a \in C\), let \(A =\{z \in C: \operatorname{Re}( a +\overline{ z }) > \operatorname{Im}(\bar{a}+z)\}\) and \(B=\{z \in C: \operatorname{Re}(a+\bar{z}) < \operatorname{Im}(\bar{a}+z)\}\). Then among the two statements : \((S 1)\) : If \(\operatorname{Re}(A), \operatorname{Im}(A) > 0\), then the set \(A\) contains all the real numbers \((S2)\): If \(\operatorname{Re}(A), \operatorname{Im}(A) < 0\), then the set \(B\) contains all the real numbers,
- A Only \((S1)\) is true
- B both are false
- C Only \((S2)\) is true
- D Both are true
Answer & Solution
Correct Answer
(B) both are false
Step-by-step Solution
Detailed explanation
Let \(a=x_1+i y_1 z=x+i y\) Now \(\operatorname{Re}(a+\bar{z}) > \operatorname{Im}(\bar{a}+z)\) \(\therefore x _1+ x >- y _1+ y\) \(x _1=2, y _1=10, x =-12, y =0\) Given inequality is not valid for these values. \(S 1\) is false. Now…
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