JEE Mains · Maths · STD 12 - 7.1 indefinite integral
\(\smallint \left( {1 + x - \frac{1}{x}} \right){e^{x + \frac{1}{x}}}\;dx = \)
- A \(\;\left( {x + 1} \right){e^{x + \frac{1}{x}}}\)
- B \( - x{e^{x + \frac{1}{x}}}\)
- C \(\left( {x - 1} \right){e^{x + \frac{1}{x}}}\)
- D \(\;x{e^{x + \frac{1}{x}}}\)
Answer & Solution
Correct Answer
(D) \(\;x{e^{x + \frac{1}{x}}}\)
Step-by-step Solution
Detailed explanation
\(\int\left(e^{x+\frac{1}{x}}+\left(x-\frac{1}{x}\right) e^{x+\frac{1}{x}}\right) d x\) ....\((1)\) \(e^{x+\frac{1}{x}}=f(x)\) \(e^{x+\frac{1}{x}}\left(1-\frac{1}{x^{2}}\right) d x=f^{\prime}(x)\)…
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