JEE Mains · Maths · STD 11 - 7. binomial theoram
The coefficient of \(x^2\) in the expansion of \(\left(2x^2 + \dfrac{1}{x}\right)^{10}\), \(x \neq 0\), is :
- A \(3240\)
- B \(3360\)
- C \(3480\)
- D \(3600\)
Answer & Solution
Correct Answer
(B) \(3360\)
Step-by-step Solution
Detailed explanation
The general term in the expansion of \(\left(2x^2 + \dfrac{1}{x}\right)^{10}\) is given by: \(T_{r+1} = ^{10}C_{r} (2x^2)^{10-r} \left(\dfrac{1}{x}\right)^r\) \(T_{r+1} = ^{10}C_{r} 2^{10-r} x^{20-2r} x^{-r}\) \(T_{r+1} = ^{10}C_{r} 2^{10-r} x^{20-3r}\) For the coefficient of…
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