JEE Mains · Maths · STD 11 - 9. straight line
A point on the straight line, \(3x + 5y = 15\) which is equidistant from the coordinate, axes will lie only in
- A \(4^{th}\) quadrant
- B \(1^{st}\) , \(2^{nd}\) and \(4^{th}\) quadrants
- C \(1^{st}\) quadrant
- D \(1^{st}\) and \(2^{nd}\) quadrants
Answer & Solution
Correct Answer
(D) \(1^{st}\) and \(2^{nd}\) quadrants
Step-by-step Solution
Detailed explanation
Now, \(\left| {\frac{{15 - 3t}}{5}} \right| = \left| t \right|\) \( \Rightarrow \frac{{15 - 3t}}{5} = t\,\,\) or \(\frac{{15 - 3t}}{5} = - t\) \(\therefore t = \frac{{15}}{8}\,\) or \(t = \frac{{ - 15}}{2}\) So, \(P\left( {\frac{{15}}{8}.\frac{{15}}{8}} \right) \in {I^{st}}\)…
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