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JEE Mains · Maths · STD 11 - 9. straight line

The base of an equilateral triangle is along the line given by \(3x + 4y\,= 9\). If a vertex of the triangle is \((1, 2)\), then the length of a side of the triangle is

  1. A \(\frac{{2\sqrt 3 }}{{15}}\)
  2. B \(\frac{{4\sqrt 3 }}{{15}}\)
  3. C \(\frac{{4\sqrt 3 }}{{5}}\)
  4. D \(\frac{{2\sqrt 3 }}{{5}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{{4\sqrt 3 }}{{15}}\)

Step-by-step Solution

Detailed explanation

Shortes distance of a point \(\left( {{x_1},{y_1}} \right)\) from line \(ax + by = c\) is \(d = \frac{{a{x_1} + b{y_1} - c}}{{\sqrt {{a^2} + {b^2}} }}\) Now shortest distance of \(P(1,2)\) from \(3x+4y=9\) is…