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JEE Mains · Maths · STD 12 - 1. relation and function

Let \(A=\{0,3,4,6,7,8,9,10\} \quad\) and \(R\) be the relation defined on A such that \(R =\{( x , y ) \in A \times A : x - y \quad\) is odd positive integer or \(x-y=2\}\). The minimum number of elements that must be added to the relation \(R\), so that it is a symmetric relation, is equal to \(...........\).

  1. A \(18\)
  2. B \(19\)
  3. C \(17\)
  4. D \(16\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(19\)

Step-by-step Solution

Detailed explanation

\(A =\{0,3,4,6,7,8,9,10\} \quad 3,7,9 \rightarrow \text { odd }\) \(R =\{ x - y =\text { odd }+ \text { ve or } x - y =2\} 0,4,6,8,10 \rightarrow \text { even }\) \({ }^3 C _1 \cdot{ }^5 C _1=15+(6,4),(8,6),(10,8),(9,7)\) \(Min ^{ m }\) ordered pairs to be added must be :…
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