JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec{a}=2 \hat{i}+5 \hat{j}-\hat{k}, \vec{b}=2 \hat{i}-2 \hat{j}+2 \hat{k}\) and \(\overrightarrow{\mathrm{c}}\) be three vectors such that \((\vec{c}+\hat{i}) \times(\vec{a}+\vec{b}+\hat{i})=\vec{a} \times(\vec{c}+\hat{i}) \cdot \vec{a} \cdot \vec{c}=-29\), then \(\overrightarrow{\mathrm{c}} \cdot(-2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}})\) is equal to :
- A \(10\)
- B \(5\)
- C \(15\)
- D \(12\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
Let's assume \(\overrightarrow{\mathrm{v}} \)\( =\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}+\hat{\mathrm{i}} \) \( =5 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+\hat{\mathrm{k}}\) and \(\overrightarrow{\mathrm{c}}+\hat{\mathrm{i}}=\overrightarrow{\mathrm{p}}\) So,…
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