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JEE Mains · Maths · STD 12 - 5. continuity and differentiation
Consider the function : \(f\left( x \right) = \left[ x \right] + \left| {1 - x} \right|,\, - 1 \le x \le 3\) where \([x]\) is the greatest integer function Statement \(1\) :\(f\) is not continuous at \(x = 0, 1, 2\) and \(3\) Statement \(2\) :\(f\left( x \right) = \left( \begin{array}{l}
- x,\,\,\,\,\,\,\,\,\, - 1 \le x < 0\\
1 - x,\,\,\,\,\,\,\,0 \le x < 1\\
1 + x,\,\,\,\,\,\,\,1 \le x < 2\,\\
2 + x,\,\,\,\,\,\,2 \le x \le 3
\end{array} \right.\)
- A Statement \(1\) is true ; Statement \(2\) is false,
- B Statement \(1\) is true; Statement \(2\) is true;Statement \(2\) is not correct explanation for Statement \(1\)
- C Statement \(1\) is true; Statement \(2\) is true;Statement It is a correct explanation for Statement \(1\).
- D Statement \(1\) is false; Statement \(2\) is true
Answer & Solution
Correct Answer
(A) Statement \(1\) is true ; Statement \(2\) is false,
Step-by-step Solution
Detailed explanation
Let \(f\left( x \right) = \left[ x \right] + \left| {1 - x} \right|, - 1 \le x \le 3\) where \([x]=\) greatest integer function. \(f\) is not continous at \(x=0,1,2,3\) But in statement - \(2\) \(f(x)\) is continuous at \(x=3\). Hence, statement - \(1\) is true and \(2\) is…
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