ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

The tangents at the point \(A (1,3)\) and \(B (1,-1)\) on the parabola \(y ^{2}-2 x -2 y =1\) meet at the point \(P\). Then the area (in unit \({ }^{2}\) ) of the triangle \(PAB\) is :-

  1. A \(4\)
  2. B \(6\)
  3. C \(7\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(8\)

Step-by-step Solution

Detailed explanation

Given curve : \(y^{2}-2 x-2 y=1\). Can be written as \((y-1)^{2}=2(x+1)\) Can be plotted as shown in figure Tangent at \(A: 2 y-x-5=0\) \({using\,T=0}\) Intersection with \(y=1\) is \(x=-3\) Hence, point \(P\) is \((-3,1)\) Taking advantage of symmetry Area of…