JEE Mains · Maths · STD 12 - 8. Application and integration
The area (in sq. units) of the region \(A = \left\{ {\left( {x,y} \right)\, \in R \times R|0 \le x \le 3,\,0 \le y \le 4|,\,y \le {x^2} + 3x} \right\}\) is
- A \(\frac{{26}}{3}\)
- B \(\frac{{59}}{6}\)
- C \(\frac{{53}}{6}\)
- D \(8\)
Answer & Solution
Correct Answer
(B) \(\frac{{59}}{6}\)
Step-by-step Solution
Detailed explanation
Required Area \( = \int\limits_0^1 {\left( {{x^2} + 3x} \right)dx + } \) Area of rectangle PQRS \(=\frac{11}{6}+8=\frac{59}{6}\)
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