JEE Mains · Maths · STD 11 - Trigonometrical equations
The angle of elevation of a cloud \(C\) from a point \(P , 200 m\) above a still lake is \(30^{\circ} .\) If the angle of depression of the image of \(C\) in the lake from the point \(P\) is \(60^{\circ},\) then \(P C\) (in \(m\) ) is equal to
- A \(400\)
- B \(400 \sqrt{3}\)
- C \(100\)
- D \(200 \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(400\)
Step-by-step Solution
Detailed explanation
Let \(P A=x\) For \(\Delta APC\) \(AC =\frac{ PA }{\sqrt{3}}=\frac{ x }{\sqrt{3}}\) \(A C^{1}=A B+B C^{1}\) \(A C^{1}=A B+B C\) \(AC ^{1}=400+\frac{ x }{\sqrt{3}}\) From \(\Delta C ^{1} PA : AC ^{1}=\sqrt{3} PA\)…
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