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JEE Mains · Maths · STD 12 - 1. relation and function

A function \(f(x)\) is given by \(f(x)=\frac{5^{x}}{5^{x}+5}\), then the sum of the series \(f\left(\frac{1}{20}\right)+f\left(\frac{2}{20}\right)+f\left(\frac{3}{20}\right)+\ldots \ldots+f\left(\frac{39}{20}\right)\) is equal to ....... .

  1. A \(\frac{19}{2}\)
  2. B \(\frac{49}{2}\)
  3. C \(\frac{29}{2}\)
  4. D \(\frac{39}{2}\)
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Answer & Solution

Correct Answer

(D) \(\frac{39}{2}\)

Step-by-step Solution

Detailed explanation

\(f(x)=\frac{5^{x}}{5^{x}+5} \quad f(2-x)=\frac{5}{5^{x}+5}\) \(f(x)+f(2-x)=1\) \(\Rightarrow f\left(\frac{1}{20}\right)+f\left(\frac{2}{20}\right)+\ldots+f\left(\frac{39}{20}\right)\)…
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