JEE Mains · Maths · STD 12 - 11. three dimension geometry
The acute angle between the planes \(P_{1}\) and \(P_{2}\), when \(P_{1}\) and \(P_{2}\) are the planes passing through the intersection of the planes \(5 x+8 y+13 z-29=0\) and \(8 x-7 y+z-20=0\) and the points \((2,1,3)\) and \((0,1,2)\), respectively, is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{12}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
Equation of plane passing through the intersection of planes \(5 x+8 y+13 z-29=0\) and \(8 x-7 y+z-\) \(20=0\) is \(5 x+8 y+3 z-29+\lambda(8 x-7 y+z-20)=0\) and if it is passing through \((2,1,3)\) then \(\lambda=\frac{7}{2}\) \(P _{1}\) : Equation of plane through intersection…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \((a, b, c)\) is the image of the point \((1,2,-3)\) in the line, \(\frac{x+1}{2}=\frac{y-3}{-2}=\frac{z}{-1},\) then \(a+b+c\) is equal toJEE Mains 2020 Medium
- Let \(\quad P=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right], A=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]\) and \(Q=P Q P^{ T }\). If \(P ^{ T } Q ^{2007} P =\left[\begin{array}{ll} a & b \\ c & d \end{array}\right]\), then \(2 a+b-3 c-4 d\) equal to \(...................\).JEE Mains 2023 Hard
- There are 12 points in a plane, no three of which are in the same straight line, except 5 points which are collinear. Then the total number of triangles that can be formed with the vertices at any three of these 12 points isJEE Mains 2025 Easy
- The surface area of a balloon of spherical shape being inflated, increases at a constant rate. If initially, the radius of balloon is \(3\) units and after \(5\) seconds, it becomes \(7\) units, then its radius after \(9\) seconds isJEE Mains 2022 Medium
- Let \([\cdot]\) denote the greatest integer function. If the domain of the function \(f(x) = \sin^{-1}\left(\dfrac{x+[x]}{3}\right)\) is \([\alpha, \beta)\), then \(\alpha^2 + \beta^2\) is equal to:JEE Mains 2026 Medium
- Let the product of the focal distances of the point \(\mathrm{P}(4,2 \sqrt{3})\) on the hyperbola \(\mathrm{H}: \frac{\mathrm{x}^2}{\mathrm{a}^2}-\frac{\mathrm{y}^2}{\mathrm{~b}^2}=1\) be 32 .
Let the length of the conjugate axis of \(H\) be \(p\) and the length of its latus rectum be q . Then \(\mathrm{p}^2+\mathrm{q}^2\) is equal to _______JEE Mains 2025 Hard
More PYQs from JEE Mains
- Let \(y=y(x)\) be the solution curve of the differential equation \(\frac{ dy }{ dx }+\frac{1}{ x ^{2}-1} y =\left(\frac{ x -1}{ x +1}\right)^{\frac{1}{2}}\), \(x>1\) passing through the point \(\left(2, \sqrt{\frac{1}{3}}\right)\). Then \(\sqrt{7} y (8)\) is equal to.JEE Mains 2022 Hard
- If \(a_n\) is the greatest term in the sequence \(a _{ n }=\frac{ n ^3}{ n ^4+147}, n =1,2,3 \ldots \ldots\). , then \(\alpha\) is equal to \(..........\).JEE Mains 2023 Hard
- If the angle between the lines, \(\frac{x}{2} = \frac{y}{2} = \frac{z}{1}\) and \(\frac{{5 - x}}{{ - 2}} = \frac{{7y - 14}}{p} = \frac{{z - 3}}{4}\) is \({\cos ^{ - 1}}\,\left( {\frac{2}{3}} \right),\) then \(p\) is equal toJEE Mains 2018 Medium
- Let \(f(x)=x^{2025}-x^{2000}, x\in[0,1]\)and the minimum value of the function \(f(x)\) in the interval [0, 1] be \((80)^{80}(n)^{-81}\). Then n is equal toJEE Mains 2026 Hard
- Let the mean and variance of the frequency distribution
be \(6\) and \(6.8\) respectively. If \(x_{3}\) is changed from \(8\) to \(7 ,\) then the mean for the new data will be:\(\mathrm{x}\) \(\mathrm{x}_{1}=2\) \(\mathrm{x}_{2}=6\) \(\mathrm{x}_{3}=8\) \(\mathrm{x}_{4}=9\) \(\mathrm{f}\) \(4\) \(4\) \(\alpha\) \(\beta\) JEE Mains 2021 Easy - Let M denote the set of all real matrices of order \(3 \times 3\) and let \(\mathrm{S}=\{-3,-2,-1,1,2\}\). Let
\(\mathrm{S}_1=\left\{\mathrm{A}=\left[a_{\mathrm{ij}}\right] \in \mathrm{M}: \mathrm{A}=\mathrm{A}^{\mathrm{T}} \text { and } a_{\mathrm{ij}} \in \mathrm{~S}, \forall \mathrm{i}, \mathrm{j}\right\}, \)
\( \mathrm{S}_2=\left\{\mathrm{A}=\left[a_{\mathrm{ij}}\right] \in \mathrm{M}: \mathrm{A}=-\mathrm{A}^{\mathrm{T}} \text { and } a_{\mathrm{ij}} \in \mathrm{~S}, \forall \mathrm{i}, \mathrm{j}\right\}, \)
\( \mathrm{S}_3=\{\mathrm{A}=\left[a_{\mathrm{ij}}\right] \in \mathrm{M}: a_{11}+a_{22}+a_{33}=0\) and \(a_{\mathrm{ij}} \in \mathrm{~S}, \forall \mathrm{i}, \mathrm{j}\}\)
If \(n\left(\mathrm{~S}_1 \cup_2 \mathrm{US}_3\right)=125 \alpha\), then \(\alpha\) equals _______JEE Mains 2025 Medium