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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Tangents drawn from the point \((- 8, 0)\) to the parabola \(y^2\, = 8x\) touch the parabola at \(P\) and \(Q\). If \(F\) is the focus of the parabola, then the area of the triangle \(PFQ\) (in sq. units) is equal to
- A \(48\)
- B \(32\)
- C \(24\)
- D \(64\)
Answer & Solution
Correct Answer
(A) \(48\)
Step-by-step Solution
Detailed explanation
Equation of the chord of contact \(PQ\) is given by: \(T=0\) or \(T = y{y_1} - 4\left( {x + {x_1}} \right)\) where \(\left( {{x_1},{y_1}} \right) \equiv \left( { - 8,0} \right)\) \(\therefore \) Equation becomes: \(x=8\) Chord of contact is \(x=8\) \(\therefore \) Coordinates of…
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