JEE Mains · Maths · STD 12 - 7.2 definite integral

Statement \(-1 :\) The value of the integral \(\mathop \smallint \limits_{\frac{\pi }{6}}^{\frac{\pi }{3}} \frac{{dx}}{{1 + \sqrt {\tan x} }} = \frac{\pi }{6}\) Statement \(-2 :\) \(\;\mathop \smallint \limits_a^b {\rm{f}}\left( {\rm{x}} \right)dx = \mathop \smallint \limits_a^b {\rm{f}}\left( {a + b - x} \right)\;dx\)

A Statement \(-1\) is true, Statement \(-2\) is true; Statement \(-2\) is not acorrect explanation for Statement \(-1\)
B Statement \(-1\) is true, Statement \(-2\) is false
C Statement \(-1\) is true, Statement \(-2\) is true; Statement \(-2\) is a correct explanation for Statement \(-1\)
D Statement \(-1\) is false, Statement \(-2\) is true

Verified Solution

Answer & Solution

Correct Answer

(D) Statement \(-1\) is false, Statement \(-2\) is true

Step-by-step Solution

Detailed explanation

\(I=\int_{\pi / 6}^{\pi / 3} \frac{d x}{1+\sqrt{\tan x}}\) \(I=\int_{\pi / 6}^{\pi / 3} \frac{\sqrt{\tan x}}{1+\sqrt{\tan x}} d x\) \(2 I=\frac{\pi}{6}\) \(I=\frac{\pi}{12}\) Therefore, l is false and II is true.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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