JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
lf a point \(P\) has co-ordinates \((0, -2)\) and \(Q\) is any point on the circle, \(x^2 + y^2 -5x - y + 5 = 0\), then the maximum value of \((PQ)^2\) is
- A \(\frac{{25 + \sqrt 6 }}{2}\)
- B \(14 + 5\sqrt 3 \)
- C \(\frac{{47 + 10\sqrt 6 }}{2}\)
- D \(8 + 5\sqrt 3 \)
Answer & Solution
Correct Answer
(B) \(14 + 5\sqrt 3 \)
Step-by-step Solution
Detailed explanation
Given that \({x^2} + {y^2} - 5x - y + 5 = 0\) \( \Rightarrow {\left( {x - 5/2} \right)^2} - \frac{{25}}{4} + {\left( {y - 1/2} \right)^2} - 1/4 = 0\) \( \Rightarrow {\left( {x - 5/2} \right)^2} + \left( {y - 1/2} \right)3/2\) on circle…
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