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JEE Mains · Maths · STD 12 - 9. differential equations

Let \(y=y(x), x>1\), be the solution of the differential equation \((x-1) \frac{d y}{d x}+2 x y=\frac{1}{x-1}\), with \(y(2)=\frac{1+e^{4}}{2 e^{4}}\). If \(y(3)=\frac{e^{\alpha}+1}{\beta e^{\alpha}}\). then the value of \(\alpha+\beta\) is equal to

  1. A \(-14\)
  2. B \(14\)
  3. C \(-24\)
  4. D \(24\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(14\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}+\frac{2 x}{x-1} \cdot y=\frac{1}{(x-1)^{2}}\) \(y=\frac{1}{(x-1)^{2}}\left[\frac{e^{2 x}+1}{2 e^{2 x}}\right]\) \(y(3)=\frac{e^{6}+1}{8 e^{6}}\) \(\alpha+\beta=14\)
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