JEE Mains · Maths · STD 11 - 14. probability
A coin is based so that a head is twice as likely to occur as a tail. If the coin is tossed \(3\) times, then the probability of getting two tails and one head is -
- A \(\frac{2}{9}\)
- B \(\frac{1}{9}\)
- C \(\frac{2}{27}\)
- D \(\frac{1}{27}\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{9}\)
Step-by-step Solution
Detailed explanation
Let probability of tail is \(\frac{1}{3}\) \(\Rightarrow\) Probability of getting head \(=\frac{2}{3}\) \(\therefore\) Probability of getting \(2\) tails and \(1\) head \(=\left(\frac{1}{3} \times \frac{2}{3} \times \frac{1}{3}\right) \times 3\) \(=\frac{2}{27} \times 3\)…
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