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JEE Mains · Maths · STD 12 - 13. probability

A biased die is marked with numbers \(2,4,8,16,32,32\) on its faces and the probability of getting a face with mark \(n\) is \(\frac{1}{n}\). If the die is thrown thrice, then the probability, that the sum of the numbers obtained is \(48\) , is

  1. A \(\frac{7}{2^{11}}\)
  2. B \(\frac{7}{2^{12}}\)
  3. C \(\frac{3}{2^{10}}\)
  4. D \(\frac{13}{2^{12}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{13}{2^{12}}\)

Step-by-step Solution

Detailed explanation

\(P ( n )=\frac{1}{ n }\) \(P (2)=\frac{1}{2} \quad P (8)=\frac{1}{8}\) \(P (4)=\frac{1}{4} \quad P (16)=\frac{1}{16}\) \(P (32)=\frac{2}{32}\) Possible cases \(16,16,16\) and \(32,8,8\) Probability…