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JEE Mains · Maths · STD 11 - 13. statistics

Let the mean of the data
\(X\) \(1\) \(3\) \(5\) \(7\) \(9\)
\((f)\) \(4\) \(24\) \(28\) \(\alpha\) \(8\)
be \(5.\) If \(m\) and \(\sigma^2\) are respectively the mean deviation about the mean and the variance of the data, then \(\frac{3 \alpha}{m+\sigma^2}\) is equal to \(..........\).

  1. A \(7\)
  2. B \(6\)
  3. C \(8\)
  4. D \(5\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(8\)

Step-by-step Solution

Detailed explanation

\(5=\bar{x}=\frac{\sum x_i f_i}{\sum f_i}=\frac{4+72+140+7 \alpha+72}{64+\alpha}\) \(\Rightarrow 320+5 \alpha=288+7 \alpha \Rightarrow 2 \alpha=32 \Rightarrow \alpha=16\)…