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JEE Mains · Maths · STD 11 - 13. statistics

Let \(X=\{11,12,13, \ldots ., 40,41\}\) and \(Y=\{61,62\), \(63, \ldots ., 90,91\}\) be the two sets of observations. If \(\bar{x}\) and \(\bar{y}\) are their respective means and \(\sigma^2\) is the variance of all the observations in \(X \cup Y\), then \(\left|\overline{ x }+\overline{ y }-\sigma^2\right|\) is equal to \(.................\).

  1. A \(603\)
  2. B \(604\)
  3. C \(605\)
  4. D \(606\)
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Answer & Solution

Correct Answer

(A) \(603\)

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Detailed explanation

\(\overline{ x }=\frac{\sum \limits_{ i =11}^{41} i }{31}=\frac{11+41}{2}=26 \quad(31 \text { elements) }\) \(\overline{ y }=\frac{\sum \limits_{ j =61}^{91} j }{31}=\frac{61+91}{2}=76 \quad \text { (31 elements) }\) \(\text { Combined mean, }\)…
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