JEE Mains · Maths · STD 12 - 10. vector algebra
Let the volume of a parallelopiped whose coterminous edges are given by \(\overrightarrow{\mathrm{u}}=\hat{\mathrm{i}}+\hat{\mathrm{j}}+\lambda \hat{\mathrm{k}}, \overrightarrow{\mathrm{v}}=\hat{\mathrm{i}}+\hat{\mathrm{j}}+3 \hat{\mathrm{k}} \) and \(\overrightarrow{\mathrm{w}}=2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}\) be \(1\; cu.\) unit. If \(\theta\) be the angle between the edges \(\overrightarrow{\mathrm{u}}\) and \(\overrightarrow{\mathrm{w}},\) then \(\cos \theta\) can be
- A \(\frac{7}{6 \sqrt{3}}\)
- B \(\frac{5}{7}\)
- C \(\frac{7}{6 \sqrt{6}}\)
- D \(\frac{5}{3 \sqrt{3}}\)
Answer & Solution
Correct Answer
(A) \(\frac{7}{6 \sqrt{3}}\)
Step-by-step Solution
Detailed explanation
\(\left|\begin{array}{lll}{1} & {1} & {\lambda} \\ {1} & {1} & {3} \\ {2} & {1} & {1}\end{array}\right|=1 \Rightarrow \lambda=2,4\)…
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