JEE Mains · Maths · STD 11 - 7. binomial theoram
Let the sum of the coefficients of the first three terms in the expansion of \(\left(x-\frac{3}{x^2}\right)^n, x \neq 0, n \in N\), be \(376\). Then the coefficient of \(x^4\) is \(......\)
- A \(404\)
- B \(403\)
- C \(402\)
- D \(405\)
Answer & Solution
Correct Answer
(D) \(405\)
Step-by-step Solution
Detailed explanation
Given Binomial \(\left(x-\frac{3}{x^2}\right)^n, x \neq 0, n \in N\) Sum of coefficients of first three terms \({ }^n C_0-{ }^n C_1 \cdot 3+{ }^n C_2 3^2=376\) \(\Rightarrow 3 n^2-5 n-250=0\) \(\Rightarrow(n-10)(3 n+25)=0\) \(\Rightarrow n =10\) Now general term…
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