JEE Mains · Maths · STD 11 - 6. permutation and combination
An eight digit number divisible by \(9\) is to be formed using digits from \(0\) to \(9\) without repeating the digits. The number of ways in which this can be done is:
- A \(72 (7!)\)
- B \(18 (7!)\)
- C \(40(7!)\)
- D \(36(7!)\)
Answer & Solution
Correct Answer
(D) \(36(7!)\)
Step-by-step Solution
Detailed explanation
We know that any number is divisible by \(9\) if sum of the digits of the number is divisible by \(9\). Now sum of the digits from \(0\) to \(9\) \(=0+1+2+3+4+5+6+7+8+9\) \(=45\) Hence to from \(8\) digits numbers which are divisible by \(9\), a pair of digits either \(0\) and…
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