JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let the lengths of intercepts on \(x\) -axis and \(y\) -axis made by the circle \(x^{2}+y^{2}+a x+2 a y+c=0\) \((a < 0)\) be \(2 \sqrt{2}\) and \(2 \sqrt{5}\), respectively. Then the shortest distance from origin to a tangent to this circle which is perpendicular to the line \(x +2 y =0,\) is euqal to :
- A \(\sqrt{11}\)
- B \(\sqrt{7}\)
- C \(\sqrt{6}\)
- D \(\sqrt{10}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{6}\)
Step-by-step Solution
Detailed explanation
\(x ^{2}+ y ^{2}+ ax +2 ay + c =0\) \(2 \sqrt{ g ^{2}- c }=2 \sqrt{\frac{ a ^{2}}{4}- c }=2 \sqrt{2}\) \(\Rightarrow \quad \frac{ a ^{2}}{4}- c =2.......(1)\) \(2 \sqrt{ f ^{2}- c }=2 \sqrt{ a ^{2}- c }=2 \sqrt{5}\) \(\Rightarrow a^{2}-c=5......(2)\) \((1)\) and \((2)\)…
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