JEE Mains · Maths · STD 12 - 8. Application and integration
Let the area of the region enclosed by the curves \(y=3 x, 2 y=27-3 x\) and \(y=3 x-x \sqrt{x}\) be \(A\). Then \(10 \mathrm{~A}\) is equal to
- A \(184\)
- B \(154\)
- C \(172\)
- D \(162\)
Answer & Solution
Correct Answer
(D) \(162\)
Step-by-step Solution
Detailed explanation
\(y=3 x, 2 y=27-3 x \& y=3 x-x \sqrt{x}\) \( \mathrm{A}=\int_0^3 3 \mathrm{x}-(3 \mathrm{x}-\mathrm{x} \sqrt{\mathrm{x}}) \mathrm{dx}+\int_3^9\left(\frac{27-3 \mathrm{x}}{2}-(3 \mathrm{x}-\mathrm{x} \sqrt{\mathrm{x}})\right) \mathrm{dx} \)…
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