JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let the locus of the mid points of the chords of circle \(x^2+(y-1)^2=1\) drawn from the origin intersect the line \(x+y=1\) at \(P\) and \(Q\). Then, the length of \(P Q\) is :
- A \(\frac{1}{\sqrt{2}}\)
- B \(\sqrt{2}\)
- C \(\frac{1}{2}\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\( \mathrm{m}_{\mathrm{OM}} \cdot \mathrm{m}_{\mathrm{CM}}=-1 \) \( \frac{\mathrm{k}}{\mathrm{h}} \cdot \frac{\mathrm{k}-1}{\mathrm{~h}}=-1\) \( \therefore \text { locus is } \mathrm{x}^2+\mathrm{y}(\mathrm{y}-1)=0 \) \( \mathrm{x}^2+\mathrm{y}^2-\mathrm{y}=0\)…
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