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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

Let \(S\) be the set of values of \(\lambda\), for which the system of equations \(6 \lambda x-3 y+3 z=4 \lambda^2\) \(2 x+6 \lambda y+4 z=1\) \(3 x+2 y+3 \lambda z=\lambda \text { has no solution. Then } 12 \sum_{\lambda \in S}|\lambda|\) is equal to \(...........\).

  1. A \(23\)
  2. B \(22\)
  3. C \(24\)
  4. D \(21\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(24\)

Step-by-step Solution

Detailed explanation

\(\Delta=\left|\begin{array}{ccc}6 \lambda & -3 & 3 \\ 2 & 6 \lambda & 4 \\ 3 & 2 & 3 \lambda\end{array}\right|=0\) (For No Solution) \(2 \lambda\left(9 \lambda^2-4\right)+(3 \lambda-6)+(2-9 \lambda)=0\) \(18 \lambda^3-14 \lambda-4=0\) \((\lambda-1)(3 \lambda+1)(3 \lambda+2)=0\)…
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