JEE Mains · Maths · STD 11 - 1. set theory
Let \(S=\{4,6,9\}\) and \(T=\{9,10,11, \ldots, 1000\}\). If \(A=\left\{a_{1}+a_{2}+\ldots+a_{k}: k \in N, a_{1}, a_{2}, a_{3}, \ldots, a_{k} \in S\right\}\) then the sum of all the elements in the set \(T - A\) is equal to \(......\)
- A \(10\)
- B \(9\)
- C \(11\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(11\)
Step-by-step Solution
Detailed explanation
\(S =\{4,6,9\} \quad T =\{9,10,11 \ldots 1000\}\) \(A \left\{ a _{1}+ a _{2}+\ldots . .+ a _{ k }: K \in N \right\} \,and\, a _{ i } \in S\) Here by the definition of set '\(A\)' \(A=\{a: a=4 x+6 y+9 z\}\) Except the element \(11\),every element of set \(T\) is of of the form…
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